Definition and examples
For nonnegative integers k, the Stirling polynomials Sk(x) are defined by the generating function equation
The first 10 Stirling polynomials are:
Yet another variant of the Stirling polynomials is considered in  (see also the subsection on Stirling convolution polynomials below).
Special values include:
                              S                      k                          (        −        m        )        =                                            (              −              1                              )                                  k                                                                                                      (                                                                      k                    +                    m                    −                    1                                    k                                                  )                                                                              S                      k            +            m            −            1            ,            m            −            1                                  , where                               S                      m            ,            n                                   denotes Stirling numbers of the second kind. Conversely,                               S                      n            ,            m                          =        (        −        1                  )                      n            −            m                                                              (                                      n              m                                      )                                                S                      n            −            m                          (        −        m        −        1        )                ;                              S                      k                          (        −        1        )        =                  δ                      k            ,            0                          ;                                              S                      k                          (        0        )        =        (        −        1                  )                      k                                    B                      k                                  , where Bk are Bernoulli numbers under the convention B1 = −1/2;                              S                      k                          (        1        )        =        (        −        1                  )                      k            +            1                          (        (        k        −        1        )                  B                      k                          +        k                  B                      k            −            1                          )                ;                              S                      k                          (        2        )        =                                            (              −              1                              )                                  k                                                      2                          (        (        k        −        1        )        (        k        −        2        )                  B                      k                          +        3        k        (        k        −        2        )                  B                      k            −            1                          +        2        k        (        k        −        1        )                  B                      k            −            2                          )                ;                              S                      k                          (        k        )        =        k        !                ;                              S                      k                          (        m        )        =                                            (              −              1                              )                                  k                                                                                                      (                                                  m                  k                                                  )                                                                              s                      m            +            1            ,            m            +            1            −            k                                  , where                               s                      m            ,            n                                   are Stirling numbers of the first kind. They may be recovered by                               s                      n            ,            m                          =        (        −        1                  )                      n            −            m                                                              (                                                      n                −                1                                            n                −                m                                                    )                                                S                      n            −            m                          (        n        −        1        )                .The sequence                               S                      k                          (        x        −        1        )                 is of binomial type, since                               S                      k                          (        x        +        y        −        1        )        =                  ∑                      i            =            0                                k                                                              (                                      k              i                                      )                                                S                      i                          (        x        −        1        )                  S                      k            −            i                          (        y        −        1        )                . Moreover, this basic recursion holds:                               S                      k                          (        x        )        =        (        x        −        k        )                                                            S                                  k                                            (              x              −              1              )                        x                          +        k                  S                      k            −            1                          (        x        +        1        )                .
Explicit representations involving Stirling numbers can be deduced with Lagrange's interpolation formula:
Here,                               L                      n                                (            α            )                                   are Laguerre polynomials.
These following relations hold as well:
                                                        (                                                      k                +                m                            k                                      )                                                S                      k                          (        x        −        m        )        =                  ∑                      i            =            0                                k                          (        −        1                  )                      k            −            i                                                              (                                                      k                +                m                            i                                      )                                                S                      k            −            i            +            m            ,            m                          ⋅                  S                      i                          (        x        )        ,                where                               S                      k            ,            n                                   is the Stirling number of the second kind and
                                                        (                                                      k                −                m                            k                                      )                                                S                      k                          (        x        +        m        )        =                  ∑                      i            =            0                                k                                                              (                                                      k                −                m                            i                                      )                                                s                      m            ,            m            −            k            +            i                          ⋅                  S                      i                          (        x        )        ,                where                               s                      k            ,            n                                   is the Stirling number of the first kind.
By differentiating the generating function it readily follows that
Closely related to Stirling polynomials are Nørlund polynomials (or generalized Bernoulli polynomials) with generating function
The relation is given by                               S                      k                          (        x        )        =                  B                      k                                (            x            +            1            )                          (        x        +        1        )                .
Another variant of the Stirling polynomial sequence corresponds to a special case of the convolution polynomials studied by Knuth's article  and in the Concrete Mathematics reference. We first define these polynomials through the Stirling numbers of the first kind as
                              σ                      n                          (        x        )        =                  [                                                                      x                                                                              x                  −                  n                                                              ]                ⋅                              1                          x              (              x              −              1              )              ⋯              (              x              −              n              )                                      .                It follows that these polynomials satisfy the next recurrence relation given by
                    (        x        +        1        )                  σ                      n                          (        x        +        1        )        =        (        x        −        n        )                  σ                      n                          (        x        )        +        x                  σ                      n            −            1                          (        x        )        ,                 n        ≥        1.                These Stirling "convolution" polynomials may be used to define the Stirling numbers,                                                         [                                                                                          x                                                                                                  x                      −                      n                                                                                  ]                                               and                                                         {                                                                                          x                                                                                                  x                      −                      n                                                                                  }                                              , for integers                     n        ≥        0                 and arbitrary complex values of                     x                . The next table provides several special cases of these Stirling polynomials for the first few                     n        ≥        0                .
This variant of the Stirling polynomial sequence has particularly nice ordinary generating functions of the following forms:
                                                                                                              (                                                                                            z                                                      e                                                          z                                                                                                                                                            e                                                          z                                                                                −                          1                                                                                      )                                                        x                                                                                              =                                  ∑                                      n                    ≥                    0                                                  x                                  σ                                      n                                                  (                x                )                                  z                                      n                                                                                                                                            (                                                                  1                        z                                                              ln                                                                                      1                                                  1                          −                          z                                                                                      )                                                        x                                                                                              =                                  ∑                                      n                    ≥                    0                                                  x                                  σ                                      n                                                  (                x                +                n                )                                  z                                      n                                                  .                                                            More generally, if                                                         S                                            t                          (        z        )                 is a power series that satisfies                     ln                          (          1          −          z                                                    S                                                    t                                (          z                      )                          t              −              1                                )                =        −        z                                            S                                            t                          (        z                  )                      t                                  , we have that
                                                        S                                            t                          (        z                  )                      x                          =                  ∑                      n            ≥            0                          x                  σ                      n                          (        x        +        t        n        )                  z                      n                          .                For integers                     0        ≤        k        ≤        n                 and                     r        ,        s        ∈                  C                        , these polynomials satisfy the two Stirling convolution formulas given by
                    (        r        +        s        )                  σ                      n                          (        r        +        s        +        t        n        )        =        r        s                  ∑                      k            =            0                                n                                    σ                      k                          (        r        +        t        k        )                  σ                      n            −            k                          (        s        +        t        (        n        −        k        )        )                and
                    n                  σ                      n                          (        r        +        s        +        t        n        )        =        s                  ∑                      k            =            0                                n                          k                  σ                      k                          (        r        +        t        k        )                  σ                      n            −            k                          (        s        +        t        (        n        −        k        )        )        .                When                     n        ,        m        ∈                  N                        , we also have that the polynomials,                               σ                      n                          (        m        )                , are defined through their relations to the Stirling numbers
                                                                                          {                                                                                                              n                                                                                                                      m                                                                                                      }                                                                            =                (                −                1                                  )                                      n                    −                    m                    +                    1                                                                                                              n                      !                                                              (                      m                      −                      1                      )                      !                                                                                        σ                                      n                    −                    m                                                  (                −                m                )                                 (                                  when                                 m                <                0                )                                                                                      [                                                                                                              n                                                                                                                      m                                                                                                      ]                                                                            =                                                                            n                      !                                                              (                      m                      −                      1                      )                      !                                                                                        σ                                      n                    −                    m                                                  (                n                )                                 (                                  when                                 m                >                n                )                ,                                                            and their relations to the Bernoulli numbers given by
                                                                                          σ                                      n                                                  (                m                )                                                            =                                                                            (                      −                      1                                              )                                                  m                          +                          n                          −                          1                                                                                                            m                      !                      (                      n                      −                      m                      )                      !                                                                                        ∑                                      0                    ≤                    k                    <                    m                                                                    [                                                                                                              m                                                                                                                      m                          −                          k                                                                                                      ]                                                                                            B                                              n                        −                        k                                                                                    n                      −                      k                                                                      ,                                 n                ≥                m                >                0                                                                                      σ                                      n                                                  (                m                )                                                            =                −                                                                            B                                              n                                                                                    n                      ⋅                      n                      !                                                                      ,                                 m                =                0.