In mathematics, the Mercator series or Newton–Mercator series is the Taylor series for the natural logarithm:
                    ln                (        1        +        x        )        =        x        −                                            x                              2                                      2                          +                                            x                              3                                      3                          −                                            x                              4                                      4                          +        ⋯                In summation notation,
                    ln                (        1        +        x        )        =                  ∑                      n            =            1                                ∞                                                              (              −              1                              )                                  n                  +                  1                                                      n                                    x                      n                          .                The series converges to the natural logarithm (shifted by 1) whenever                     −        1        <        x        ≤        1                 .
The series was discovered independently by Nicholas Mercator, Isaac Newton and Gregory Saint-Vincent. It was first published by Mercator, in his 1668 treatise Logarithmotechnia.
The series can be obtained from Taylor's theorem, by inductively computing the nth derivative of                     ln                (        x        )                 at                     x        =        1                 , starting with
                                          d                          d              x                                      ln                (        x        )        =                              1            x                          .                Alternatively, one can start with the finite geometric series (                    t        ≠        −        1                )
                    1        −        t        +                  t                      2                          −        ⋯        +        (        −        t                  )                      n            −            1                          =                                            1              −              (              −              t                              )                                  n                                                                    1              +              t                                              which gives
                                          1                          1              +              t                                      =        1        −        t        +                  t                      2                          −        ⋯        +        (        −        t                  )                      n            −            1                          +                                            (              −              t                              )                                  n                                                                    1              +              t                                      .                It follows that
                              ∫                      0                                x                                                              d              t                                      1              +              t                                      =                  ∫                      0                                x                                    (          1          −          t          +                      t                          2                                −          ⋯          +          (          −          t                      )                          n              −              1                                +                                                    (                −                t                                  )                                      n                                                                              1                +                t                                              )                         d        t                and by termwise integration,
                    ln                (        1        +        x        )        =        x        −                                            x                              2                                      2                          +                                            x                              3                                      3                          −        ⋯        +        (        −        1                  )                      n            −            1                                                              x                              n                                      n                          +        (        −        1                  )                      n                                    ∫                      0                                x                                                              t                              n                                                    1              +              t                                               d        t        .                If                     −        1        <        x        ≤        1                 , the remainder term tends to 0 as                     n        →        ∞                .
This expression may be integrated iteratively k more times to yield
                    −        x                  A                      k                          (        x        )        +                  B                      k                          (        x        )        ln                (        1        +        x        )        =                  ∑                      n            =            1                                ∞                          (        −        1                  )                      n            −            1                                                              x                              n                +                k                                                    n              (              n              +              1              )              ⋯              (              n              +              k              )                                      ,                where
                              A                      k                          (        x        )        =                              1                          k              !                                                ∑                      m            =            0                                k                                                              (                                      k              m                                      )                                                x                      m                                    ∑                      l            =            1                                k            −            m                                                              (              −              x                              )                                  l                  −                  1                                                      l                                  and
                              B                      k                          (        x        )        =                              1                          k              !                                      (        1        +        x                  )                      k                                  are polynomials in x.
Setting                     x        =        1                 in the Mercator series yields the alternating harmonic series
                              ∑                      k            =            1                                ∞                                                              (              −              1                              )                                  k                  +                  1                                                      k                          =        ln                (        2        )        .                The complex power series
                              ∑                      n            =            1                                ∞                                                              z                              n                                      n                          =        z        +                                            z                              2                                      2                          +                                            z                              3                                      3                          +                                            z                              4                                      4                          +        ⋯                is the Taylor series for                     −        log                (        1        −        z        )                 , where log denotes the principal branch of the complex logarithm. This series converges precisely for all complex number                               |                z                  |                ≤        1        ,        z        ≠        1                . In fact, as seen by the ratio test, it has radius of convergence equal to 1, therefore converges absolutely on every disk B(0, r) with radius r < 1. Moreover, it converges uniformly on every nibbled disk                                                                         B                (                0                ,                1                )                            ¯                                ∖          B          (          1          ,          δ          )                        , with δ > 0. This follows at once from the algebraic identity:
                    (        1        −        z        )                  ∑                      n            =            1                                m                                                              z                              n                                      n                          =        z        −                  ∑                      n            =            2                                m                                                              z                              n                                                    n              (              n              −              1              )                                      −                                            z                              m                +                1                                      m                          ,                observing that the right-hand side is uniformly convergent on the whole closed unit disk.