The quadratic Hill yield criterion has the form
                    F        (                  σ                      22                          −                  σ                      33                                    )                      2                          +        G        (                  σ                      33                          −                  σ                      11                                    )                      2                          +        H        (                  σ                      11                          −                  σ                      22                                    )                      2                          +        2        L                  σ                      23                                2                          +        2        M                  σ                      31                                2                          +        2        N                  σ                      12                                2                          =        1                 .                Here F, G, H, L, M, N are constants that have to be determined experimentally and                               σ                      i            j                                   are the stresses. The quadratic Hill yield criterion depends only on the deviatoric stresses and is pressure independent. It predicts the same yield stress in tension and in compression.
If the axes of material anisotropy are assumed to be orthogonal, we can write
                    (        G        +        H        )                 (                  σ                      1                                y                                    )                      2                          =        1                 ;                          (        F        +        H        )                 (                  σ                      2                                y                                    )                      2                          =        1                 ;                          (        F        +        G        )                 (                  σ                      3                                y                                    )                      2                          =        1                where                               σ                      1                                y                          ,                  σ                      2                                y                          ,                  σ                      3                                y                                   are the normal yield stresses with respect to the axes of anisotropy. Therefore we have
                    F        =                                                                                                                          1                                                                                                                                                  2                                                                              [                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              2                                                                    y                                                                                    )                                              2                                                                                                                          +                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              3                                                                    y                                                                                    )                                              2                                                                                                                          −                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              1                                                                    y                                                                                    )                                              2                                                                                                                          ]                                            G        =                                                                                                                          1                                                                                                                                                  2                                                                              [                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              3                                                                    y                                                                                    )                                              2                                                                                                                          +                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              1                                                                    y                                                                                    )                                              2                                                                                                                          −                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              2                                                                    y                                                                                    )                                              2                                                                                                                          ]                                            H        =                                                                                                                          1                                                                                                                                                  2                                                                              [                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              1                                                                    y                                                                                    )                                              2                                                                                                                          +                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              2                                                                    y                                                                                    )                                              2                                                                                                                          −                                                                                                                                            1                                                                                                                                                                      (                                          σ                                              3                                                                    y                                                                                    )                                              2                                                                                                                          ]                        Similarly, if                               τ                      12                                y                          ,                  τ                      23                                y                          ,                  τ                      31                                y                                   are the yield stresses in shear (with respect to the axes of anisotropy), we have
                    L        =                                                                                                                          1                                                                                                                                                  2                                     (                                      τ                                          23                                                              y                                                                            )                                          2                                                                                                                   ;                          M        =                                                                                                                          1                                                                                                                                                  2                                     (                                      τ                                          31                                                              y                                                                            )                                          2                                                                                                                   ;                          N        =                                                                                                                          1                                                                                                                                                  2                                     (                                      τ                                          12                                                              y                                                                            )                                          2                                                                                                                  The quadratic Hill yield criterion for thin rolled plates (plane stress conditions) can be expressed as
                              σ                      1                                2                          +                                                                                                                                              R                                          0                                                                           (                  1                  +                                      R                                          90                                                        )                                                                                                                                                                      R                                          90                                                                           (                  1                  +                                      R                                          0                                                        )                                                                                       σ                      2                                2                          −                                                                                                                          2                                                         R                                          0                                                                                                                                                                                        1                  +                                      R                                          0                                                                                                                             σ                      1                                    σ                      2                          =        (                  σ                      1                                y                                    )                      2                                  where the principal stresses                               σ                      1                          ,                  σ                      2                                   are assumed to be aligned with the axes of anisotropy with                               σ                      1                                   in the rolling direction and                               σ                      2                                   perpendicular to the rolling direction,                               σ                      3                          =        0                ,                               R                      0                                   is the R-value in the rolling direction, and                               R                      90                                   is the R-value perpendicular to the rolling direction.
For the special case of transverse isotropy we have                     R        =                  R                      0                          =                  R                      90                                   and we get
                              σ                      1                                2                          +                  σ                      2                                2                          −                                                                                                                          2                                     R                                                                                                                                                  1                  +                  R                                                                                       σ                      1                                    σ                      2                          =        (                  σ                      1                                y                                    )                      2                                  The generalized Hill yield criterion has the form
                                                                        F                                  |                                                  σ                                      2                                                  −                                  σ                                      3                                                                                        |                                                        m                                                                                              +                G                                  |                                                  σ                                      3                                                  −                                  σ                                      1                                                                                        |                                                        m                                                  +                H                                  |                                                  σ                                      1                                                  −                                  σ                                      2                                                                                        |                                                        m                                                  +                L                                  |                                2                                  σ                                      1                                                  −                                  σ                                      2                                                  −                                  σ                                      3                                                                                        |                                                        m                                                                                                                                    +                M                                  |                                2                                  σ                                      2                                                  −                                  σ                                      3                                                  −                                  σ                                      1                                                                                        |                                                        m                                                  +                N                                  |                                2                                  σ                                      3                                                  −                                  σ                                      1                                                  −                                  σ                                      2                                                                                        |                                                        m                                                  =                                  σ                                      y                                                        m                                                                   .                                                            where                               σ                      i                                   are the principal stresses (which are aligned with the directions of anisotropy),                               σ                      y                                   is the yield stress, and F, G, H, L, M, N are constants. The value of m is determined by the degree of anisotropy of the material and must be greater than 1 to ensure convexity of the yield surface.
For transversely isotropic materials with                     1        −        2                 being the plane of symmetry, the generalized Hill yield criterion reduces to (with                     F        =        G                 and                     L        =        M                )
                                                                        f                :=                                            F                                  |                                                  σ                                      2                                                  −                                  σ                                      3                                                                                        |                                                        m                                                  +                F                                  |                                                  σ                                      3                                                  −                                  σ                                      1                                                                                        |                                                        m                                                  +                H                                  |                                                  σ                                      1                                                  −                                  σ                                      2                                                                                        |                                                        m                                                  +                L                                  |                                2                                  σ                                      1                                                  −                                  σ                                      2                                                  −                                  σ                                      3                                                                                        |                                                        m                                                                                                                                    +                L                                  |                                2                                  σ                                      2                                                  −                                  σ                                      3                                                  −                                  σ                                      1                                                                                        |                                                        m                                                  +                N                                  |                                2                                  σ                                      3                                                  −                                  σ                                      1                                                  −                                  σ                                      2                                                                                        |                                                        m                                                  −                                  σ                                      y                                                        m                                                  ≤                0                                                            The R-value or Lankford coefficient can be determined by considering the situation where                               σ                      1                          >        (                  σ                      2                          =                  σ                      3                          =        0        )                . The R-value is then given by
                    R        =                                                                                                                          (                                      2                                          m                      −                      1                                                        +                  2                  )                  L                  −                  N                  +                  H                                                                                                                                                  (                                      2                                          m                      −                      1                                                        −                  1                  )                  L                  +                  2                  N                  +                  F                                                                             .                Under plane stress conditions and with some assumptions, the generalized Hill criterion can take several forms.
Case 1:                     L        =        0        ,        H        =        0.                                    f        :=                                                                                                                          1                  +                  2                  R                                                                                                                                                  1                  +                  R                                                                    (                  |                          σ                      1                                                |                                m                          +                  |                          σ                      2                                                |                                m                          )        −                                                                                                                          R                                                                                                                                                  1                  +                  R                                                                              |                          σ                      1                          +                  σ                      2                                                |                                m                          −                  σ                      y                                m                          ≤        0                Case 2:                     N        =        0        ,        F        =        0.                                    f        :=                                                                                                                                              2                                          m                      −                      1                                                        (                  1                  −                  R                  )                  +                  (                  R                  +                  2                  )                                                                                                                                                  (                  1                  −                                      2                                          m                      −                      1                                                        )                  (                  1                  +                  R                  )                                                                              |                          σ                      1                          −                  σ                      2                                                |                                m                          −                                                                                                                          1                                                                                                                                                  (                  1                  −                                      2                                          m                      −                      1                                                        )                  (                  1                  +                  R                  )                                                                    (                  |                2                  σ                      1                          −                  σ                      2                                                |                                m                          +                  |                2                  σ                      2                          −                  σ                      1                                                |                                m                          )        −                  σ                      y                                m                          ≤        0                Case 3:                     N        =        0        ,        H        =        0.                                    f        :=                                                                                                                                              2                                          m                      −                      1                                                        (                  1                  −                  R                  )                  +                  (                  R                  +                  2                  )                                                                                                                                                  (                  2                  +                                      2                                          m                      −                      1                                                        )                  (                  1                  +                  R                  )                                                                    (                  |                          σ                      1                                                |                                m                          −                  |                          σ                      2                                                |                                m                          )        +                                                                                                                          R                                                                                                                                                  (                  2                  +                                      2                                          m                      −                      1                                                        )                  (                  1                  +                  R                  )                                                                    (                  |                2                  σ                      1                          −                  σ                      2                                                |                                m                          +                  |                2                  σ                      2                          −                  σ                      1                                                |                                m                          )        −                  σ                      y                                m                          ≤        0                Case 4:                     L        =        0        ,        F        =        0.                                    f        :=                                                                                                                          1                  +                  2                  R                                                                                                                                                  2                  (                  1                  +                  R                  )                                                                              |                          σ                      1                          −                  σ                      2                                                |                                m                          +                                                                                                                          1                                                                                                                                                  2                  (                  1                  +                  R                  )                                                                              |                          σ                      1                          +                  σ                      2                                                |                                m                          −                  σ                      y                                m                          ≤        0                Case 5:                     L        =        0        ,        N        =        0.                . This is the Hosford yield criterion.                    f        :=                                                                                                                          1                                                                                                                                                  1                  +                  R                                                                    (                  |                          σ                      1                                                |                                m                          +                  |                          σ                      2                                                |                                m                          )        +                                                                                                                          R                                                                                                                                                  1                  +                  R                                                                              |                          σ                      1                          −                  σ                      2                                                |                                m                          −                  σ                      y                                m                          ≤        0                Care must be exercised in using these forms of the generalized Hill yield criterion because the yield surfaces become concave (sometimes even unbounded) for certain combinations of                     R                 and 
                    m                .
In 1993, Hill proposed another yield criterion  for plane stress problems with planar anisotropy. The Hill93 criterion has the form
                                          (                                                                                                                                                                                      σ                                                  1                                                                                                                                                                                                                                                                σ                                                  0                                                                                                                                          )                                2                          +                              (                                                                                                                                                                                      σ                                                  2                                                                                                                                                                                                                                                                σ                                                  90                                                                                                                                          )                                2                          +                  [          (          p          +          q          −          c          )          −                                                                                                                                            p                                          σ                                              1                                                              +                    q                                          σ                                              2                                                                                                                                                                                                                                      σ                                              b                                                                                                                          ]                          (                                                                                                                                                                  σ                                              1                                                                                    σ                                              2                                                                                                                                                                                                                                      σ                                              0                                                                                    σ                                              90                                                                                                                          )                =        1                where                               σ                      0                                   is the uniaxial tensile yield stress in the rolling direction,                               σ                      90                                   is the uniaxial tensile yield stress in the direction normal to the rolling direction,                               σ                      b                                   is the yield stress under uniform biaxial tension, and                     c        ,        p        ,        q                 are parameters defined as
                                                                        c                                                            =                                                                                                                                                                                                                              σ                                                          0                                                                                                                                                                                                                                                                                                                    σ                                                          90                                                                                                                                                                          +                                                                                                                                                                                                                              σ                                                          90                                                                                                                                                                                                                                                                                                                    σ                                                          0                                                                                                                                                                          −                                                                                                                                                                                                                              σ                                                          0                                                                                                            σ                                                          90                                                                                                                                                                                                                                                                                                                    σ                                                          b                                                                                      2                                                                                                                                                                                                                                                (                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              0                                                                                                                                                                                          +                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              90                                                                                                                                                                                          −                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              b                                                                                                                                                                                          )                                                 p                                                            =                                                                                                                                                                                                  2                                                      R                                                          0                                                                                (                                                      σ                                                          b                                                                                −                                                      σ                                                          90                                                                                )                                                                                                                                                                                                                                  (                          1                          +                                                      R                                                          0                                                                                )                                                      σ                                                          0                                                                                      2                                                                                                                                                                          −                                                                                                                                                                                                  2                                                      R                                                          90                                                                                                            σ                                                          b                                                                                                                                                                                                                                                                                        (                          1                          +                                                      R                                                          90                                                                                )                                                      σ                                                          90                                                                                      2                                                                                                                                                                          +                                                                                                                                                                                                  c                                                                                                                                                                                                                                                              σ                                                          0                                                                                                                                                                                                                                                (                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              0                                                                                                                                                                                          +                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              90                                                                                                                                                                                          −                                                                                                                                                                                                                    1                                                                                                                                                                                                                                                                                    σ                                                              b                                                                                                                                                                                          )                                                 q                                                            =                                                                                                                                                                                                  2                                                      R                                                          90                                                                                (                                                      σ                                                          b                                                                                −                                                      σ                                                          0                                                                                )                                                                                                                                                                                                                                  (                          1                          +                                                      R                                                          90                                                                                )                                                      σ                                                          90                                                                                      2                                                                                                                                                                          −                                                                                                                                                                                                  2                                                      R                                                          0                                                                                                            σ                                                          b                                                                                                                                                                                                                                                                                        (                          1                          +                                                      R                                                          0                                                                                )                                                      σ                                                          0                                                                                      2                                                                                                                                                                          +                                                                                                                                                                                                  c                                                                                                                                                                                                                                                              σ                                                          90                                                                                                                                                                                                                      and                               R                      0                                   is the R-value for uniaxial tension in the rolling direction, and                               R                      90                                   is the R-value for uniaxial tension in the in-plane direction perpendicular to the rolling direction.
The original versions of Hill's yield criteria were designed for material that did not have pressure-dependent yield surfaces which are needed to model polymers and foams.
An extension that allows for pressure dependence is Caddell-Raghava-Atkins (CRA) model  which has the form
                    F        (                  σ                      22                          −                  σ                      33                                    )                      2                          +        G        (                  σ                      33                          −                  σ                      11                                    )                      2                          +        H        (                  σ                      11                          −                  σ                      22                                    )                      2                          +        2        L                  σ                      23                                2                          +        2        M                  σ                      31                                2                          +        2        N                  σ                      12                                2                          +        I                  σ                      11                          +        J                  σ                      22                          +        K                  σ                      33                          =        1                 .                The Deshpande-Fleck-Ashby yield criterion
Another pressure-dependent extension of Hill's quadratic yield criterion which has a form similar to the Bresler Pister yield criterion is the Deshpande, Fleck and Ashby (DFA) yield criterion  for honeycomb structures (used in sandwich composite construction). This yield criterion has the form
                    F        (                  σ                      22                          −                  σ                      33                                    )                      2                          +        G        (                  σ                      33                          −                  σ                      11                                    )                      2                          +        H        (                  σ                      11                          −                  σ                      22                                    )                      2                          +        2        L                  σ                      23                                2                          +        2        M                  σ                      31                                2                          +        2        N                  σ                      12                                2                          +        K        (                  σ                      11                          +                  σ                      22                          +                  σ                      33                                    )                      2                          =        1                 .