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Extensions of symmetric operators

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In functional analysis, one is interested in extensions of symmetric operators acting on a Hilbert space. Of particular importance is the existence, and sometimes explicit constructions, of self-adjoint extensions. This problem arises, for example, when one needs to specify domains of self-adjointness for formal expressions of observables in quantum mechanics. Other applications of solutions to this problem can be seen in various moment problems.

Contents

This article discusses a few related problems of this type. The unifying theme is that each problem has an operator-theoretic characterization which gives a corresponding parametrization of solutions. More specifically, finding self-adjoint extensions, with various requirements, of symmetric operators is equivalent to finding unitary extensions of suitable partial isometries.

Symmetric operators

Let H be a Hilbert space. A linear operator A acting on H with dense domain Dom(A) is symmetric if

<Ax, y> = <x, Ay>, for all x, y in Dom(A).

If Dom(A) = H, the Hellinger-Toeplitz theorem says that A is a bounded operator, in which case A is self-adjoint and the extension problem is trivial. In general, a symmetric operator is self-adjoint if the domain of its adjoint, Dom(A*), lies in Dom(A).

When dealing with unbounded operators, it is often desirable to be able to assume that the operator in question is closed. In the present context, it is a convenient fact that every symmetric operator A is closable. That is, A has a smallest closed extension, called the closure of A. This can be shown by invoking the symmetric assumption and Riesz representation theorem. Since A and its closure have the same closed extensions, it can always be assumed that the symmetric operator of interest is closed.

In the sequel, a symmetric operator will be assumed to be densely defined and closed.

Problem Given a densely defined closed symmetric operator A, find its self-adjoint extensions.

This question can be translated to an operator-theoretic one. As a heuristic motivation, notice that the Cayley transform on the complex plane, defined by

z z i z + i

maps the real line to the unit circle. This suggests one define, for a symmetric operator A,

U A = ( A i ) ( A + i ) 1

on Ran(A + i), the range of A + i. The operator UA is in fact an isometry between closed subspaces that takes (A + i)x to (A - i)x for x in Dom(A). The map

A U A

is also called the Cayley transform of the symmetric operator A. Given UA, A can be recovered by

A = i ( U + 1 ) ( U 1 ) 1 ,

defined on Dom(A) = Ran(U - 1). Now if

U ~

is an isometric extension of UA, the operator

A ~ = i ( U ~ + 1 ) ( U ~ 1 ) 1

acting on

R a n ( i 2 ( U ~ 1 ) ) = R a n ( U ~ 1 )

is a symmetric extension of A.

Theorem The symmetric extensions of a closed symmetric operator A is in one-to-one correspondence with the isometric extensions of its Cayley transform UA.

Of more interest is the existence of self-adjoint extensions. The following is true.

Theorem A closed symmetric operator A is self-adjoint if and only if Ran (A ± i) = H, i.e. when its Cayley transform UA is a unitary operator on H.

Corollary The self-adjoint extensions of a closed symmetric operator A is in one-to-one correspondence with the unitary extensions of its Cayley transform UA.

Define the deficiency subspaces of A by

K + = R a n ( A + i )

and

K = R a n ( A i ) .

In this language, the description of the self-adjoint extension problem given by the corollary can be restated as follows: a symmetric operator A has self-adjoint extensions if and only if its Cayley transform UA has unitary extensions to H, i.e. the deficiency subspaces K+ and K have the same dimension.

An example

Consider the Hilbert space L2[0,1]. On the subspace of absolutely continuous function that vanish on the boundary, define the operator A by

A f = i d d x f .

Integration by parts shows A is symmetric. Its adjoint A* is the same operator with Dom(A*) being the absolutely continuous functions with no boundary condition. We will see that extending A amounts to modifying the boundary conditions, thereby enlarging Dom(A) and reducing Dom(A*), until the two coincide.

Direct calculation shows that K+ and K are one-dimensional subspaces given by

K + = s p a n { ϕ + = a e x }

and

K = s p a n { ϕ = a e x }

where a is a normalizing constant. So the self-adjoint extensions of A are parametrized by the unit circle in the complex plane, {| α | = 1}. For each unitary Uα : KK+, defined by Uα(φ) = αφ+, there corresponds an extension Aα with domain

D o m ( A α ) = { f + β ( α ϕ ϕ + ) | f D o m ( A ) , β C } .

If f ∈ Dom(Aα), then f is absolutely continuous and

| f ( 0 ) f ( 1 ) | = | e α 1 α e | = 1.

Conversely, if f is absolutely continuous and f(0) = γf(1) for some complex γ with |γ| = 1, then f lies in the above domain.

The self-adjoint operators { Aα } are instances of the momentum operator in quantum mechanics.

Self-adjoint extension on a larger space

Every partial isometry can be extended, on a possibly larger space, to a unitary operator. Consequently, every symmetric operator has a self-adjoint extension, on a possibly larger space.

Positive symmetric operators

A symmetric operator A is called positive if <Ax, x> ≥ 0 for all x in Dom(A). It is known that for every such A, one has dim(K+) = dim(K). Therefore, every positive symmetric operator has self-adjoint extensions. The more interesting question in this direction is whether A has positive self-adjoint extensions.

For two positive operators A and B, we put AB if

( A + 1 ) 1 ( B + 1 ) 1

in the sense of bounded operators.

Structure of 2 × 2 matrix contractions

While the extension problem for general symmetric operators is essentially that of extending partial isometries to unitaries, for positive symmetric operators the question becomes one of extending contractions: by "filling out" certain unknown entries of a 2 × 2 self-adjoint contraction, we obtain the positive self-adjoint extensions of a positive symmetric operator.

Before stating the relevant result, we first fix some terminology. For a contraction Γ, acting on H, we define its defect operators by

D Γ = ( 1 Γ Γ ) 1 2 and D Γ = ( 1 Γ Γ ) 1 2 .

The defect spaces of Γ are

D Γ = R a n ( D Γ ) and D Γ = R a n ( D Γ ) .

The defect operators indicate the non-unitarity of Γ, while the defect spaces ensure uniqueness in some parameterizations. Using this machinery, one can explicitly describe the structure of general matrix contractions. We will only need the 2 × 2 case. Every 2 × 2 contraction Γ can be uniquely expressed as

Γ = [ Γ 1 D Γ 1 Γ 2 Γ 3 D Γ 1 Γ 3 Γ 1 Γ 2 + D Γ 3 Γ 4 D Γ 2 ]

where each Γi is a contraction.

Extensions of Positive symmetric operators

The Cayley transform for general symmetric operators can be adapted to this special case. For every non-negative number a,

| a 1 a + 1 | 1.

This suggests we assign to every positive symmetric operator A a contraction

C A : R a n ( A + 1 ) R a n ( A 1 ) H

defined by

C A ( A + 1 ) x = ( A 1 ) x . i.e. C A = ( A 1 ) ( A + 1 ) 1 .

which have matrix representation

C A = [ Γ 1 Γ 3 D Γ 1 ] : R a n ( A + 1 ) R a n ( A + 1 ) R a n ( A + 1 ) .

It is easily verified that the Γ1 entry, CA projected onto Ran(A + 1) = Dom(CA), is self-adjoint. The operator A can be written as

A = ( 1 + C A ) ( 1 C A ) 1

with Dom(A) = Ran(CA - 1). If

C ~

is a contraction that extends CA and its projection onto its domain is self-adjoint, then it is clear that its inverse Cayley transform

A ~ = ( 1 + C ~ ) ( 1 C ~ ) 1

defined on

R a n ( 1 C ~ )

is a positive symmetric extension of A. The symmetric property follows from its projection onto its own domain being self-adjoint and positivity follows from contractivity. The converse is also true: given a positive symmetric extension of A, its Cayley transform is a contraction satisfying the stated "partial" self-adjoint property.

Theorem The positive symmetric extensions of A are in one-to-one correspondence with the extensions of its Cayley transform where if C is such an extension, we require C projected onto Dom(C) be self-adjoint.

The unitarity criterion of the Cayley transform is replaced by self-adjointness for positive operators.

Theorem A symmetric positive operator A is self-adjoint if and only if its Cayley transform is a self-adjoint contraction defined on all of H, i.e. when Ran(A + 1) = H.

Therefore, finding self-adjoint extension for a positive symmetric operator becomes a "matrix completion problem". Specifically, we need to embed the column contraction CA into a 2 × 2 self-adjoint contraction. This can always be done and the structure of such contractions gives a parametrization of all possible extensions.

By the preceding subsection, all self-adjoint extensions of CA takes the form

C ~ ( Γ 4 ) = [ Γ 1 D Γ 1 Γ 3 Γ 3 D Γ 1 Γ 3 Γ 1 Γ 3 + D Γ 3 Γ 4 D Γ 3 ] .

So the self-adjoint positive extensions of A are in bijective correspondence with the self-adjoint contractions Γ4 on the defect space

D Γ 3

of Γ3. The contractions

C ~ ( 1 ) and C ~ ( 1 )

give rise to positive extensions

A 0 and A

respectively. These are the smallest and largest positive extensions of A in the sense that

A 0 B A

for any positive self-adjoint extension B of A. The operator A is the Friedrichs extension of A and A0 is the von Neumann-Krein extension of A.

Similar results can be obtained for accretive operators.

References

Extensions of symmetric operators Wikipedia


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