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Exact differential equation

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In mathematics, an exact differential equation or total differential equation is a certain kind of ordinary differential equation which is widely used in physics and engineering.

Contents

Definition

Given a simply connected and open subset D of R2 and two functions I and J which are continuous on D then an implicit first-order ordinary differential equation of the form

I ( x , y ) d x + J ( x , y ) d y = 0 ,

is called an exact differential equation if there exists a continuously differentiable function F, called the potential function, so that

F x = I

and

F y = J .

The nomenclature of "exact differential equation" refers to the exact derivative of a function. For a function F ( x 0 , x 1 , . . . , x n 1 , x n ) , the exact or total derivative with respect to x 0 is given by

d F d x 0 = F x 0 + i = 1 n F x i d x i d x 0 .

Example

The function F : R 2 R given by

F ( x , y ) = 1 2 ( x 2 + y 2 )

is a potential function for the differential equation

x d x + y d y = 0.

Existence of potential functions

In physical applications the functions I and J are usually not only continuous but even continuously differentiable. Schwarz's Theorem then provides us with a necessary criterion for the existence of a potential function. For differential equations defined on simply connected sets the criterion is even sufficient and we get the following theorem:

Given a differential equation of the form (for example, when F has zero slope in the x and y direction at F(x,y) ):

I ( x , y ) d x + J ( x , y ) d y = 0 ,

with I and J continuously differentiable on a simply connected and open subset D of R2 then a potential function F exists if and only if

I y ( x , y ) = J x ( x , y ) .

Solutions to exact differential equations

Given an Exact differential equation defined on some simply connected and open subset D of R2 with potential function F then a differentiable function f with (x, f(x)) in D is a solution if and only if there exists real number c so that

F ( x , f ( x ) ) = c .

For an initial value problem

y ( x 0 ) = y 0

we can locally find a potential function by

F ( x , y ) = x 0 x I ( t , y 0 ) d t + y 0 y J ( x , t ) d t = x 0 x I ( t , y 0 ) d t + y 0 y [ J ( x 0 , t ) + x 0 x I t ( u , t ) d u ] d t .

Solving

F ( x , y ) = c

for y, where c is a real number, we can then construct all solutions.

References

Exact differential equation Wikipedia