In mathematics, the tensor product
Contents
- Tensor product of vector spaces
- The free vector space
- Definition
- Notation
- Dimension
- Tensor product of linear maps
- Universal property
- Tensor powers and braiding
- Product of tensors
- Relation to dual space
- Tensor product vs Hom
- Adjoint representation
- Tensor products of modules over a ring
- Computing the tensor product
- Tensor product of algebras
- Eigenconfigurations of tensors
- Tensor product of multilinear forms
- Tensor product of graphs
- Monoidal categories
- Exterior and symmetric algebra
- Array programming languages
- References
The tensor product of (finite dimensional) vector spaces has dimension equal to the product of the dimensions of the two factors:
In particular, this distinguishes the tensor product from the direct sum vector space, whose dimension is the sum of the two summands:
More generally, the tensor product can be extended to other categories of mathematical objects in addition to vector spaces, such as to matrices, tensors, algebras, topological vector spaces, and modules. In each such case the tensor product is characterized by a similar universal property: it is the freest bilinear operation. The general concept of a "tensor product" is captured by monoidal categories; that is, the class of all things that have a tensor product is a monoidal category. The
Tensor product of vector spaces
The tensor product of two vector spaces V and W over a field K is another vector space over K. It is denoted V ⊗K W, or V ⊗ W when the underlying field K is understood.
If
As an example, letting
The above definition relies on a choice of basis, which can not be done canonically for a generic vector space. However, any two choices of basis lead to isomorphic tensor product spaces (c.f. the universal property described below). Alternatively, the tensor product may be defined in an expressly basis-independent manner as a quotient space of a free vector space over V × W. This approach is described below.
The free vector space
The definition of ⊗ requires the notion of the free vector space F(S) on some set S, a vector space whose basis is parameterized by S. F(S) is defined as the set of all functions g from S to a given field K that have finite support; i.e., g is identically zero outside some finite subset of S. It is a vector space over K with the usual addition and scalar multiplication of functions. It has a basis parameterized by S. Indeed, for each s in S we define
Then {δs | s ∈ S} is a basis for F(S), since each element g of F(S) can be uniquely written as a linear combination of δs, and because of the restriction that g has finite support, this linear combination consists of finitely many terms. Because of this explicit expression, an element of F(S) is often called a formal sum of symbols in S.
By construction, the (possibly infinite) dimension of the vector space F(S) equals the cardinality of the set S.
Definition
Let us first consider a special case: let us say V, W are free vector spaces for the sets S, T respectively. That is, V = F(S), W = F(T). In this special case, the tensor product is defined as F(S) ⊗ F(T) = F(S × T). In most typical cases, any vector space can be immediately understood as the free vector space for some set, so this definition suffices. However, there is also an explicit way of constructing the tensor product directly from V, W, without appeal to S, T.
In general, given two vector spaces V and W over a field K, the tensor product U of V and W, denoted as U = V ⊗ W is defined as the vector space whose elements and operations are constructed as follows:
From the Cartesian product V × W, the free vector space F(V × W) over K is formed. The vectors of V ⊗ W are then defined to be the equivalence classes of the congruence generated by the following relations on F(V × W):
The operations of V ⊗ W, i.e. the map of vector addition + : U × U → U and scalar multiplication ⋅ : K × U → U are defined to be the respective operations +F and ⋅F from F(V × W), acting on any representatives
in the involved equivalence classes outputting the one equivalence class of the result.
The result can be proven to be independent of which representatives of the involved classes have been chosen. In other words, the operations are well-defined.
In other words, the tensor product V ⊗ W is defined as the quotient space F(V × W)/N, where N is the subspace of F(V × W) consisting of the equivalence class of the zero element, N = [∅], ∅ ∈ F(V × W), under the equivalence relation of above. In this way, because it is a quotient of the free vector space by the subspace generated by the relations, it is the freest such vector space. For this reason, the tensor product
The following expression explicitly gives the subspace N:
In the quotient, where N is mapped to the zero vector, the following equalities,
all hold (unlike in F(V × W)), which is exactly what is desired. In these latter expressions, the (v1, w), etc., are images in the quotient of vectors in the free product under the quotient map. Usually, some other notation is employed for them, see below.
Notation
Elements of V ⊗ W are often referred to as tensors, although this term refers to many other related concepts as well. If v belongs to V and w belongs to W, then the equivalence class of (v, w) is denoted by v ⊗ w, which is called the tensor product of v with w. In physics and engineering, this use of the "⊗" symbol refers specifically to the outer product operation; the result of the outer product v ⊗ w is one of the standard ways of representing the equivalence class v ⊗ w. An element of V ⊗ W that can be written in the form v ⊗ w is called a pure or simple tensor. In general, an element of the tensor product space is not a pure tensor, but rather a finite linear combination of pure tensors. For example, if v1 and v2 are linearly independent, and w1 and w2 are also linearly independent, then v1 ⊗ w1 + v2 ⊗ w2 cannot be written as a pure tensor. The number of simple tensors required to express an element of a tensor product is called the tensor rank (not to be confused with tensor order, which is the number of spaces one has taken the product of, in this case 2; in notation, the number of indices), and for linear operators or matrices, thought of as (1, 1) tensors (elements of the space V ⊗ V∗), it agrees with matrix rank.
Dimension
Given bases {vi} and {wj} for V and W respectively, the tensors {vi ⊗ wj} form a basis for V ⊗ W. Therefore, if V and W are finite-dimensional, the dimension of the tensor product is the product of dimensions of the original spaces; for instance Rm ⊗ Rn is isomorphic to Rmn.
Tensor product of linear maps
The tensor product also operates on linear maps between vector spaces. Specifically, given two linear maps S : V → X and T : W → Y between vector spaces, the tensor product of the two linear maps S and T is a linear map
defined by
In this way, the tensor product becomes a bifunctor from the category of vector spaces to itself, covariant in both arguments.
If S and T are both injective, surjective, or continuous then S ⊗ T is, respectively, injective, surjective, continuous.
By choosing bases of all vector spaces involved, the linear maps S and T can be represented by matrices. Then, the matrix describing the tensor product S ⊗ T is the Kronecker product of the two matrices. For example, if V, X, W, and Y above are all two-dimensional and bases have been fixed for all of them, and S and T are given by the matrices
respectively, then the tensor product of these two matrices is
The resultant rank is at most 4, and thus the resultant dimension is 4. Here rank denotes the tensor rank (number of requisite indices), while the matrix rank counts the number of degrees of freedom in the resulting array.
A dyadic product is the special case of the tensor product between two vectors of the same dimension.
Universal property
The tensor product as defined above satisfies a universal property. In this context, this means that the tensor product is uniquely defined, up to isomorphism: there is only one tensor product. In the context of linear algebra and vector spaces, the maps in question are required to be linear maps. The tensor product of vector spaces, as defined above, satisfies the following universal property: there is a bilinear map (i.e., linear in each variable v and w) φ : V × W → V ⊗ W such that given any other vector space Z together with a bilinear map h : V × W → Z, there is a unique linear map ~h : V ⊗ W → Z satisfying h = ~h ∘ φ. In this sense, φ is the most general bilinear map that can be built from V × W. In particular, this implies that any spaces with such a (uniquely defined) tensor product are examples of symmetric monoidal categories, as this is the defining characteristic of the category. Uniqueness of the tensor product means that for any other bilinear map φ′ : V × W → V ⊗′ W with the above property there is an isomorphism k : V ⊗ W → V ⊗′ W such that φ′ = k ∘ φ holds.
This characterization can simplify proving statements about the tensor product. For example, the tensor product is symmetric: that is, there is a canonical isomorphism:
To construct, say, a map from left to right, it suffices, by the universal property, to give a bilinear map V × W → W ⊗ V. This is done by mapping (v, w) to w ⊗ v. Constructing a map in the opposite direction is done similarly, as is checking that the two linear maps V ⊗ W → W ⊗ V and W ⊗ V → V ⊗ W are inverse to one another.
Similar reasoning can be used to show that the tensor product is associative, that is, there are natural isomorphisms
Therefore, it is customary to omit the parentheses and write V1 ⊗ V2 ⊗ V3.
Tensor powers and braiding
Let n be a non-negative integer. The nth tensor power of the vector space V is the n-fold tensor product of V with itself. That is
A permutation σ of the set {1, 2, ..., n} determines a mapping of the nth Cartesian power of V as follows:
Let
be the natural multilinear embedding of the Cartesian power of V into the tensor power of V. Then, by the universal property, there is a unique isomorphism
such that
The isomorphism τσ is called the braiding map associated to the permutation σ.
Product of tensors
For non-negative integers r and s a type (r,s) tensor on a vector space V is an element of
Here V∗ is the dual vector space (which consists of all linear maps f from V to the ground field K).
There is a product map, called the (tensor) product of tensors
It is defined by grouping all occurring "factors" V together: writing vi for an element of V and fi for elements of the dual space,
Picking a basis of V and the corresponding dual basis of V∗ naturally induces a basis for Tr
s(V) (this basis is described in the article on Kronecker products). In terms of these bases, the components of a (tensor) product of two (or more) tensors can be computed. For example, if F and G are two covariant tensors of rank m and n respectively (i.e. F ∈ T 0
m, and G ∈ T 0
n), then the components of their tensor product are given by
Thus, the components of the tensor product of two tensors are the ordinary product of the components of each tensor. Another example: let U be a tensor of type (1, 1) with components Uαβ, and let V be a tensor of type (1, 0) with components V γ. Then
and
Relation to dual space
A particular example is the tensor product of some vector space V with its dual vector space V∗ (which consists of all linear maps f from V to the ground field K). In this case, there is a canonical evaluation map
which on elementary tensors is defined by
The resulting map
is called tensor contraction (for r, s > 0).
On the other hand, if V is finite-dimensional, there is a canonical map in the other direction (called the coevaluation map)
where v1, ..., vn is any basis of V, and vi∗ is its dual basis. Surprisingly, this map does not depend on our choice of basis.
The interplay of evaluation and coevaluation map can be used to characterize finite-dimensional vector spaces without referring to bases.
Tensor product vs. Hom
Given two finite dimensional vector spaces U, V, denote the dual space of U as U*, we have the following relation:
an isomorphism can be defined by
its "inverse" can be defined in a similar manner as above (Relation to dual space) using dual basis
This result implies
which automatically gives the important fact that
Furthermore, given three vector spaces U, V, W the tensor product is linked to the vector space of all linear maps, as follows:
Here Hom(-,-) denotes the K-vector space of all linear maps. This is an example of adjoint functors: the tensor product is "left adjoint" to Hom.
Adjoint representation
The tensor
where u∗ in End(V∗) is the transpose of u, that is, in terms of the obvious pairing on V ⊗ V∗,
There is a canonical isomorphism
Under this isomorphism, every u in End(V) may be first viewed as an endomorphism of
Tensor products of modules over a ring
The tensor product of two modules A and B over a commutative ring R is defined in exactly the same way as the tensor product of vector spaces over a field:
where now F(A × B) is the free R-module generated by the cartesian product and G is the R-module generated by the same relations as above.
More generally, the tensor product can be defined even if the ring is non-commutative (ab ≠ ba). In this case A has to be a right-R-module and B is a left-R-module, and instead of the last two relations above, the relation
is imposed. If R is non-commutative, this is no longer an R-module, but just an abelian group.
The universal property also carries over, slightly modified: the map φ : A × B → A ⊗R B defined by (a, b) ↦ a ⊗ b is a middle linear map (referred to as "the canonical middle linear map".); that is, it satisfies:
The first two properties make φ a bilinear map of the abelian group A × B. For any middle linear map ψ of A × B, a unique group homomorphism f of A ⊗R B satisfies ψ = f ∘ φ, and this property determines
Computing the tensor product
For vector spaces, the tensor product V ⊗ W is quickly computed since bases of V of W immediately determine a basis of V ⊗ W, as was mentioned above. For modules over a general (commutative) ring, not every module is free. For example, Z/nZ is not a free abelian group (= Z-module). The tensor product with Z/nZ is given by
More generally, given a presentation of some R-module M, that is, a number of generators mi ∈ M, i ∈ I together with relations
Here NJ := ⨁j ∈ J N and the map is determined by sending some n ∈ N in the jth copy of NJ to ajin (in NI). Colloquially, this may be rephrased by saying that a presentation of M gives rise to a presentation of M ⊗R N. This is referred to by saying that the tensor product is a right exact functor. It is not in general left exact, that is, given an injective map of R-modules M1 → M2, the tensor product
is not usually injective. For example, tensoring the (injective) map given by multiplication with n, n : Z → Z with Z/nZ yields the zero map 0 : Z/nZ → Z/nZ, which is not injective. Higher Tor functors measure the defect of the tensor product being not left exact. All higher Tor functors are assembled in the derived tensor product.
Tensor product of algebras
Let R be a commutative ring. The tensor product of R-modules applies, in particular, if A and B are R-algebras. In this case, the tensor product A ⊗R B is an R-algebra itself by putting
For example,
A particular example is when A and B are fields containing a common subfield R. The tensor product of fields is closely related to Galois theory: if, say, A = R[x] / f(x), where f is some irreducible polynomial with coefficients in R, the tensor product can be calculated as
where now f is interpreted as the same polynomial, but with its coefficients regarded as elements of B. In the larger field B, the polynomial may become reducible, which brings in Galois theory. For example, if A = B is a Galois extension of R, then
is isomorphic (as an A-algebra) to the Adeg(f).
Eigenconfigurations of tensors
Square matrices A with entries in a field K represent linear maps of vector spaces, say
Thus each of the
and the eigenconfiguration is given by the variety of the
Tensor product of multilinear forms
Given two multilinear forms
This is a special case of the product of tensors if they are seen as multilinear maps (see also tensors as multilinear maps). Thus the components of the tensor product of multilinear forms can be computed by the Kronecker product.
Tensor product of graphs
It should be mentioned that, though called "tensor product", this is not a tensor product of graphs in the above sense; actually it is the category-theoretic product in the category of graphs and graph homomorphisms. However it is actually the Kronecker tensor product of the adjacency matrices of the graphs. Compare also the section Tensor product of linear maps above.
Monoidal categories
A general context for tensor product is that of a monoidal category.
Exterior and symmetric algebra
Two notable constructions in linear algebra can be constructed as quotients of the tensor product: the exterior algebra and the symmetric algebra. For example, given a vector space V, the exterior product
is defined as
Note that when the underlying field of V does not have characteristic 2, then this definition is equivalent to
The image of
The symmetric algebra is constructed in a similar manner:
That is, in the symmetric algebra two adjacent vectors (and therefore all of them) can be interchanged. The resulting objects are called symmetric tensors.
Array programming languages
Array programming languages may have this pattern built in. For example, in APL the tensor product is expressed as ○.×
(for example A ○.× B
or A ○.× B ○.× C
). In J the tensor product is the dyadic form of */
(for example a */ b
or a */ b */ c
).
Note that J's treatment also allows the representation of some tensor fields, as a
and b
may be functions instead of constants. This product of two functions is a derived function, and if a
and b
are differentiable, then a */ b
is differentiable.
However, these kinds of notation are not universally present in array languages. Other array languages may require explicit treatment of indices (for example, MATLAB), and/or may not support higher-order functions such as the Jacobian derivative (for example, Fortran/APL).