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Q derivative

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In mathematics, in the area of combinatorics, the q-derivative, or Jackson derivative, is a q-analog of the ordinary derivative, introduced by Frank Hilton Jackson. It is the inverse of Jackson's q-integration.

Contents

Definition

The q-derivative of a function f(x) is defined as

( d d x ) q f ( x ) = f ( q x ) f ( x ) q x x .

It is also often written as D q f ( x ) . The q-derivative is also known as the Jackson derivative.

Formally, in terms of Lagrange's shift operator in logarithmic variables, it amounts to the operator

D q = 1 x   q d       d ( ln x ) 1 q 1   ,

which goes to the plain derivative, → ddx, as q → 1.

It is manifestly linear,

D q ( f ( x ) + g ( x ) ) = D q f ( x ) + D q g ( x )   .

It has product rule analogous to the ordinary derivative product rule, with two equivalent forms

D q ( f ( x ) g ( x ) ) = g ( x ) D q f ( x ) + f ( q x ) D q g ( x ) = g ( q x ) D q f ( x ) + f ( x ) D q g ( x ) .

Similarly, it satisfies a quotient rule,

D q ( f ( x ) / g ( x ) ) = g ( x ) D q f ( x ) f ( x ) D q g ( x ) g ( q x ) g ( x ) , g ( x ) g ( q x ) 0.

There is also a rule similar to the chain rule for ordinary derivatives. Let g ( x ) = c x k . Then

D q f ( g ( x ) ) = D q k ( f ) ( g ( x ) ) D q ( g ) ( x ) .

The eigenfunction of the q-derivative is the q-exponential eq(x).

Relationship to ordinary derivatives

Q-differentiation resembles ordinary differentiation, with curious differences. For example, the q-derivative of the monomial is:

( d d z ) q z n = 1 q n 1 q z n 1 = [ n ] q z n 1

where [ n ] q is the q-bracket of n. Note that lim q 1 [ n ] q = n so the ordinary derivative is regained in this limit.

The n-th q-derivative of a function may be given as:

( D q n f ) ( 0 ) = f ( n ) ( 0 ) n ! ( q ; q ) n ( 1 q ) n = f ( n ) ( 0 ) n ! [ n ] q !

provided that the ordinary n-th derivative of f exists at x = 0. Here, ( q ; q ) n is the q-Pochhammer symbol, and [ n ] q ! is the q-factorial. If f ( x ) is analytic we can apply the Taylor formula to the definition of D q ( f ( x ) ) to get

D q ( f ( x ) ) = k = 0 ( q 1 ) k ( k + 1 ) ! x k f ( k + 1 ) ( x ) .

A q-analog of the Taylor expansion of a function about zero follows:

f ( z ) = n = 0 f ( n ) ( 0 ) z n n ! = n = 0 ( D q n f ) ( 0 ) z n [ n ] q !

References

Q-derivative Wikipedia