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Dual norm

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In functional analysis, the dual norm is a measure of the "size" of continuous linear functionals.

Contents

Definition

Let X and Y be topological vector spaces, and L ( X , Y ) be the collection of all bounded linear mappings (or operators) of X into Y . In the case where X and Y are normed vector spaces, L ( X , Y ) can be normed in a natural way.

When Y is a scalar field (i.e. Y = C or Y = R ) so that L ( X , Y ) is the dual space X of X , the norm on L ( X , Y ) defines a topology on X which turns out to be stronger than its weak-*topology.

Theorem 1: Let X and Y be normed spaces, and associate to each f L ( X , Y ) the number:

f = sup { | f ( x ) | : x X , x 1 }

We first establish that L ( X , Y ) is bounded (using the triangle inequality), and complete (using Cauchy sequences) using our definition of f , thereby making L ( X , Y ) a normed space. If Y is a Banach space, so is L ( X , Y ) .

Proof:

  1. A subset of a normed space is bounded if and only if it lies in some multiple of the unit sphere; thus f < for every f L ( X , Y ) if α is a scalar, then ( α f ) ( x ) = α f x so that α f = | α | f The triangle inequality in Y shows that ( f 1 + f 2 ) x = f 1 x + f 2 x f 1 x + f 2 x ( f 1 + f 2 ) x f 1 + f 2 for every x X with x 1 . Thus f 1 + f 2 f 1 + f 2 If f 0 , then f x 0 for some x X ; hence f > 0 . Thus, L ( X , Y ) is a normed space.
  2. Assume now that Y is complete, and that { f n } is a Cauchy sequence in L ( X , Y ) . Since and it is assumed that f n f m 0 as n and m tend to , { f n x } is a Cauchy sequence in Y for every x X . Hence exists. It is clear that f : X Y is linear. If ε > 0 , f n f m x ε x for sufficiently large n and m. It follows f x f m x ε x for sufficiently large m. Hence f x ( f m + ε ) x , so that f L ( X , Y ) and f f m ε . Thus f m f in the norm of L ( X , Y ) . This establishes the completeness of L ( X , Y )

Theorem 2: Now suppose B is the closed unit ball of normed space X . Define

x = sup { | x , x | : x B }

for every x X

The second dual of a Banach space is an isometric isomorphism

The normed dual X of a Banach space X is also a Banach space, which means it has a normed dual, X , of its own.

By part (b) of Theorem 2, every x X defines a unique ϕ X by equation

x , x = x , ϕ x ( x X ) ;

and

ϕ x = x ( x X ) .

It follows from the first and second equation that ϕ : X X is linear and ϕ is an isometry. Given that X is assumed to be complete, ϕ ( X ) is closed in X .

Thus, ϕ is an isometric isomorphism onto a closed subspace of X .

The members of ϕ ( x ) are exactly the linear functionals on X that are continuous with respect to its weak*-topology. Since the norm topology of X is stronger, may happen that ϕ ( X ) is a proper subspace of X .

However, there are many important spaces, such as the Lp spaces with 1 < p < , where ϕ ( X ) = X ; these are called reflexive.

It is stressed that, for X to be reflexive, the existence of some isometric isomorphism ϕ of X onto X is not enough; it is crucial that ϕ satisfies first equation in this section.

Mathematical Optimization

Let | | | | be a norm on R n . The associated dual norm, denoted , is defined as

| | z | | = sup { z x | | | x | | 1 } .

(This can be shown to be a norm.) The dual norm can be interpreted as the operator norm of z , interpreted as a 1 × n matrix, with the norm | | | | on R n , and the absolute value on R :

| | z | | = sup { | z x | | | | x | | 1 } .

From the definition of dual norm we have the inequality

z x x z

which holds for all x and z. The dual of the dual norm is the original norm: we have x = x for all x. (This need not hold in infinite-dimensional vector spaces.)

The dual of the Euclidean norm is the Euclidean norm, since

sup { z x | x 2 1 } = z 2 .

(This follows from the Cauchy-Schwarz inequality; for nonzero z, the value of x that maximises z x over x 2 1 is z z 2 .)

The dual of the 1 -norm is the -norm:

sup { z x | x 1 } = i = 1 n | z i | = z 1 ,

and the dual of the -norm is the 1 -norm.

More generally, Hölder's inequality shows that the dual of the p -norm is the q -norm, where, q satisfies 1 p + 1 q = 1 , i.e., q = p p 1 .

As another example, consider the 2 - or spectral norm on R m × n . The associated dual norm is

Z 2 = sup { t r ( Z X ) | X 2 1 } ,

which turns out to be the sum of the singular values,

Z 2 = σ 1 ( Z ) + + σ r ( Z ) = t r ( Z Z ) 1 2 ,

where r = r a n k Z . This norm is sometimes called the nuclear norm.

Dual norm for matrices

The Frobenius norm defined by A F = i = 1 m j = 1 n | a i j | 2 = trace ( A A ) = i = 1 min { m , n } σ i 2 is self-dual, i.e., its dual norm is F = F . The spectral norm, a special case of the induced norm when p = 2 , is defined by the maximum singular values of a matrix, i.e., A 2 = σ m a x ( A ) , has dual norm defined by B 2 = i σ i ( B ) for any matrix B where σ i ( B ) denote the singular values.

References

Dual norm Wikipedia