Season 1947–48 | Teams 6 | |
Champions Baltimore Bullets (1st title) Runner-up Philadelphia Warriors (2nd finals appearance) |
The 1948 BAA Playoffs was the postseason tournament following the Basketball Association of America 1947–48 season. (Following its third, 1948–49 season, the BAA and National Basketball League merged to create the National Basketball Association or NBA.) The tournament concluded with the Baltimore Bullets defeating the Philadelphia Warriors 4 games to 2 in the BAA Finals.
Contents
The two Division champions and two teams involved in a 3-way tiebreaker began tournament play on Tuesday, March 23, and the Finals concluded on Wednesday, April 21. Baltimore and Philadelphia played 12 and 13 games in the span of 30 days; their six final games in 12 days.
Bracket
There were no byes. Western and Eastern champions St. Louis and Philadelphia immediately played a long semifinal series with St. Louis having home-court advantage. Philadelphia won the seventh game in St. Louis, 85–46, two days before Baltimore concluded its sequence of tie-breaker (not shown) and two short series with other runners-up.
Western Division tiebreaker
Chicago Stags vs. Washington Capitols: Stags win series 1-0
Chicago Stags vs. Baltimore Bullets: Bullets win series 1-0
First Round
(W2) Baltimore Bullets vs. (E2) New York Knicks: Bullets win series 2-1
This was the first playoff series between the Bullets and Knicks.
(E3) Boston Celtics vs. (W3) Chicago Stags: Stags win series 2-1
This was the first playoff series between the Celtics and Stags.
Semifinals
(W1) St. Louis Bombers vs. (E1) Philadelphia Warriors: Warriors win series 4-3
Last playoff meeting: 1947 BAA First Round (Philadelphia won 2-1)
(W2) Baltimore Bullets vs. (W3) Chicago Stags: Bullets win series 2-0
This was the first playoff series between the Bullets and Stags.
BAA Finals
(E1) Philadelphia Warriors vs. (W2) Baltimore Bullets: Bullets win series 4-2
This was the first playoff series between the Warriors and Bullets.