The Yeoh hyperelastic material model is a phenomenological model for the deformation of nearly incompressible, nonlinear elastic materials such as rubber. The model is based on Ronald Rivlin's observation that the elastic properties of rubber may be described using a strain energy density function which is a power series in the strain invariants 
  
    
      
        
          I
          
            1
          
        
        ,
        
          I
          
            2
          
        
        ,
        
          I
          
            3
          
        
      
    
    
   of the Cauchy-Green deformation tensors. The Yeoh model for incompressible rubber is a function only of 
  
    
      
        
          I
          
            1
          
        
      
    
    
  . For compressible rubbers, a dependence on 
  
    
      
        
          I
          
            3
          
        
      
    
    
   is added on. Since a polynomial form of the strain energy density function is used but all the three invariants of the left Cauchy-Green deformation tensor are not, the Yeoh model is also called the reduced polynomial model.
The original model proposed by Yeoh had a cubic form with only 
  
    
      
        
          I
          
            1
          
        
      
    
    
   dependence and is applicable to purely incompressible materials. The strain energy density for this model is written as
  
    
      
        W
        =
        
          ∑
          
            i
            =
            1
          
          
            3
          
        
        
          C
          
            i
          
        
         
        (
        
          I
          
            1
          
        
        −
        3
        
          )
          
            i
          
        
      
    
    
  
where 
  
    
      
        
          C
          
            i
          
        
      
    
    
   are material constants. The quantity 
  
    
      
        2
        
          C
          
            1
          
        
      
    
    
   can be interpreted as the initial shear modulus.
Today a slightly more generalized version of the Yeoh model is used. This model includes 
  
    
      
        n
      
    
    
   terms and is written as
  
    
      
        W
        =
        
          ∑
          
            i
            =
            1
          
          
            n
          
        
        
          C
          
            i
          
        
         
        (
        
          I
          
            1
          
        
        −
        3
        
          )
          
            i
          
        
         
        .
      
    
    
  
When 
  
    
      
        n
        =
        1
      
    
    
   the Yeoh model reduces to the neo-Hookean model for incompressible materials.
For consistency with linear elasticity the Yeoh model has to satisfy the condition
  
    
      
        2
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        (
        3
        )
        =
        μ
         
         
        (
        i
        ≠
        j
        )
      
    
    
  
where 
  
    
      
        μ
      
    
    
   is the shear modulus of the material. Now, at 
  
    
      
        
          I
          
            1
          
        
        =
        3
        (
        
          λ
          
            i
          
        
        =
        
          λ
          
            j
          
        
        =
        1
        )
      
    
    
  ,
  
    
      
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          C
          
            1
          
        
      
    
    
  
Therefore, the consistency condition for the Yeoh model is
  
    
      
        2
        
          C
          
            1
          
        
        =
        μ
        
      
    
    
  
The Cauchy stress for the incompressible Yeoh model is given by
  
    
      
        
          σ
        
        =
        −
        p
         
        
          
            1
          
        
        +
        2
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        
          B
        
         
        ;
         
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          ∑
          
            i
            =
            1
          
          
            n
          
        
        i
         
        
          C
          
            i
          
        
         
        (
        
          I
          
            1
          
        
        −
        3
        
          )
          
            i
            −
            1
          
        
         
        .
      
    
    
  
For uniaxial extension in the 
  
    
      
        
          
            n
          
          
            1
          
        
      
    
    
  -direction, the principal stretches are 
  
    
      
        
          λ
          
            1
          
        
        =
        λ
        ,
         
        
          λ
          
            2
          
        
        =
        
          λ
          
            3
          
        
      
    
    
  . From incompressibility 
  
    
      
        
          λ
          
            1
          
        
         
        
          λ
          
            2
          
        
         
        
          λ
          
            3
          
        
        =
        1
      
    
    
  . Hence 
  
    
      
        
          λ
          
            2
          
          
            2
          
        
        =
        
          λ
          
            3
          
          
            2
          
        
        =
        1
        
          /
        
        λ
      
    
    
  . Therefore,
  
    
      
        
          I
          
            1
          
        
        =
        
          λ
          
            1
          
          
            2
          
        
        +
        
          λ
          
            2
          
          
            2
          
        
        +
        
          λ
          
            3
          
          
            2
          
        
        =
        
          λ
          
            2
          
        
        +
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
         
        .
      
    
    
  
The left Cauchy-Green deformation tensor can then be expressed as
  
    
      
        
          B
        
        =
        
          λ
          
            2
          
        
         
        
          
            n
          
          
            1
          
        
        ⊗
        
          
            n
          
          
            1
          
        
        +
        
          
            
              
                
              
              
                
                  1
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
         
        (
        
          
            n
          
          
            2
          
        
        ⊗
        
          
            n
          
          
            2
          
        
        +
        
          
            n
          
          
            3
          
        
        ⊗
        
          
            n
          
          
            3
          
        
        )
         
        .
      
    
    
  
If the directions of the principal stretches are oriented with the coordinate basis vectors, we have
  
    
      
        
          σ
          
            11
          
        
        =
        −
        p
        +
        2
         
        
          λ
          
            2
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        ;
         
         
        
          σ
          
            22
          
        
        =
        −
        p
        +
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          σ
          
            33
          
        
         
        .
      
    
    
  
Since 
  
    
      
        
          σ
          
            22
          
        
        =
        
          σ
          
            33
          
        
        =
        0
      
    
    
  , we have
  
    
      
        p
        =
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
Therefore,
  
    
      
        
          σ
          
            11
          
        
        =
        2
         
        
          (
          
            λ
            
              2
            
          
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    λ
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
The engineering strain is 
  
    
      
        λ
        −
        1
        
      
    
    
  . The engineering stress is
  
    
      
        
          T
          
            11
          
        
        =
        
          σ
          
            11
          
        
        
          /
        
        λ
        =
        2
         
        
          (
          λ
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        2
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
For equibiaxial extension in the 
  
    
      
        
          
            n
          
          
            1
          
        
      
    
    
   and 
  
    
      
        
          
            n
          
          
            2
          
        
      
    
    
   directions, the principal stretches are 
  
    
      
        
          λ
          
            1
          
        
        =
        
          λ
          
            2
          
        
        =
        λ
        
      
    
    
  . From incompressibility 
  
    
      
        
          λ
          
            1
          
        
         
        
          λ
          
            2
          
        
         
        
          λ
          
            3
          
        
        =
        1
      
    
    
  . Hence 
  
    
      
        
          λ
          
            3
          
        
        =
        1
        
          /
        
        
          λ
          
            2
          
        
        
      
    
    
  . Therefore,
  
    
      
        
          I
          
            1
          
        
        =
        
          λ
          
            1
          
          
            2
          
        
        +
        
          λ
          
            2
          
          
            2
          
        
        +
        
          λ
          
            3
          
          
            2
          
        
        =
        2
         
        
          λ
          
            2
          
        
        +
        
          
            
              
                
              
              
                
                  1
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      4
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
The left Cauchy-Green deformation tensor can then be expressed as
  
    
      
        
          B
        
        =
        
          λ
          
            2
          
        
         
        
          
            n
          
          
            1
          
        
        ⊗
        
          
            n
          
          
            1
          
        
        +
        
          λ
          
            2
          
        
         
        
          
            n
          
          
            2
          
        
        ⊗
        
          
            n
          
          
            2
          
        
        +
        
          
            
              
                
              
              
                
                  1
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      4
                    
                  
                
              
            
          
        
         
        
          
            n
          
          
            3
          
        
        ⊗
        
          
            n
          
          
            3
          
        
         
        .
      
    
    
  
If the directions of the principal stretches are oriented with the coordinate basis vectors, we have
  
    
      
        
          σ
          
            11
          
        
        =
        −
        p
        +
        2
         
        
          λ
          
            2
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          σ
          
            22
          
        
         
        ;
         
         
        
          σ
          
            33
          
        
        =
        −
        p
        +
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      4
                    
                  
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
Since 
  
    
      
        
          σ
          
            33
          
        
        =
        0
      
    
    
  , we have
  
    
      
        p
        =
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      4
                    
                  
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
Therefore,
  
    
      
        
          σ
          
            11
          
        
        =
        2
         
        
          (
          
            λ
            
              2
            
          
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        4
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          σ
          
            22
          
        
         
        .
      
    
    
  
The engineering strain is 
  
    
      
        λ
        −
        1
        
      
    
    
  . The engineering stress is
  
    
      
        
          T
          
            11
          
        
        =
        
          
            
              
                
              
              
                
                  
                    σ
                    
                      11
                    
                  
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
        =
        2
         
        
          (
          λ
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        5
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
        =
        
          T
          
            22
          
        
         
        .
      
    
    
  
Planar extension tests are carried out on thin specimens which are constrained from deforming in one direction. For planar extension in the 
  
    
      
        
          
            n
          
          
            1
          
        
      
    
    
   directions with the 
  
    
      
        
          
            n
          
          
            3
          
        
      
    
    
   direction constrained, the principal stretches are 
  
    
      
        
          λ
          
            1
          
        
        =
        λ
        ,
         
        
          λ
          
            3
          
        
        =
        1
      
    
    
  . From incompressibility 
  
    
      
        
          λ
          
            1
          
        
         
        
          λ
          
            2
          
        
         
        
          λ
          
            3
          
        
        =
        1
      
    
    
  . Hence 
  
    
      
        
          λ
          
            2
          
        
        =
        1
        
          /
        
        λ
        
      
    
    
  . Therefore,
  
    
      
        
          I
          
            1
          
        
        =
        
          λ
          
            1
          
          
            2
          
        
        +
        
          λ
          
            2
          
          
            2
          
        
        +
        
          λ
          
            3
          
          
            2
          
        
        =
        
          λ
          
            2
          
        
        +
        
          
            
              
                
              
              
                
                  1
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      2
                    
                  
                
              
            
          
        
        +
        1
         
        .
      
    
    
  
The left Cauchy-Green deformation tensor can then be expressed as
  
    
      
        
          B
        
        =
        
          λ
          
            2
          
        
         
        
          
            n
          
          
            1
          
        
        ⊗
        
          
            n
          
          
            1
          
        
        +
        
          
            
              
                
              
              
                
                  1
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      2
                    
                  
                
              
            
          
        
         
        
          
            n
          
          
            2
          
        
        ⊗
        
          
            n
          
          
            2
          
        
        +
        
          
            n
          
          
            3
          
        
        ⊗
        
          
            n
          
          
            3
          
        
         
        .
      
    
    
  
If the directions of the principal stretches are oriented with the coordinate basis vectors, we have
  
    
      
        
          σ
          
            11
          
        
        =
        −
        p
        +
        2
         
        
          λ
          
            2
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        ;
         
         
        
          σ
          
            22
          
        
        =
        −
        p
        +
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      2
                    
                  
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        ;
         
         
        
          σ
          
            33
          
        
        =
        −
        p
        +
        2
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
Since 
  
    
      
        
          σ
          
            22
          
        
        =
        0
      
    
    
  , we have
  
    
      
        p
        =
        
          
            
              
                
              
              
                
                  2
                
              
            
            
              
                
              
              
                
                  
                    λ
                    
                      2
                    
                  
                
              
            
          
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
Therefore,
  
    
      
        
          σ
          
            11
          
        
        =
        2
         
        
          (
          
            λ
            
              2
            
          
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        2
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        ;
         
         
        
          σ
          
            22
          
        
        =
        0
         
        ;
         
         
        
          σ
          
            33
          
        
        =
        2
         
        
          (
          1
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        2
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
The engineering strain is 
  
    
      
        λ
        −
        1
        
      
    
    
  . The engineering stress is
  
    
      
        
          T
          
            11
          
        
        =
        
          
            
              
                
              
              
                
                  
                    σ
                    
                      11
                    
                  
                
              
            
            
              
                
              
              
                
                  λ
                
              
            
          
        
        =
        2
         
        
          (
          λ
          −
          
            
              
                
                  
                
                
                  
                    1
                  
                
              
              
                
                  
                
                
                  
                    
                      λ
                      
                        3
                      
                    
                  
                
              
            
          
          )
        
         
        
          
            
              
                
              
              
                
                  ∂
                  W
                
              
            
            
              
                
              
              
                
                  ∂
                  
                    I
                    
                      1
                    
                  
                
              
            
          
        
         
        .
      
    
    
  
A version of the Yeoh model that includes 
  
    
      
        
          I
          
            3
          
        
        =
        
          J
          
            2
          
        
      
    
    
   dependence is used for compressible rubbers. The strain energy density function for this model is written as
  
    
      
        W
        =
        
          ∑
          
            i
            =
            1
          
          
            n
          
        
        
          C
          
            i
            0
          
        
         
        (
        
          
            
              
                I
                ¯
              
            
          
          
            1
          
        
        −
        3
        
          )
          
            i
          
        
        +
        
          ∑
          
            k
            =
            1
          
          
            n
          
        
        
          C
          
            k
            1
          
        
         
        (
        J
        −
        1
        
          )
          
            2
            k
          
        
      
    
    
  
where 
  
    
      
        
          
            
              
                I
                ¯
              
            
          
          
            1
          
        
        =
        
          J
          
            −
            2
            
              /
            
            3
          
        
         
        
          I
          
            1
          
        
      
    
    
  , and 
  
    
      
        
          C
          
            i
            0
          
        
        ,
        
          C
          
            k
            1
          
        
      
    
    
   are material constants. The quantity 
  
    
      
        
          C
          
            10
          
        
      
    
    
   is interpreted as half the initial shear modulus, while 
  
    
      
        
          C
          
            11
          
        
      
    
    
   is interpreted as half the initial bulk modulus.
When 
  
    
      
        n
        =
        1
      
    
    
   the compressible Yeoh model reduces to the neo-Hookean model for incompressible materials.