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United States presidential election in Indiana, 1840

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October 30 - December 2, 1840
  
1844 →

65,302
  
51,604

42
  
0

55.86%
  
44.14%

United States presidential election in Indiana, 1840

The 1840 United States presidential election in Indiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Indiana by a margin of 11.72%.

References

United States presidential election in Indiana, 1840 Wikipedia


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