Samiksha Jaiswal (Editor)

Chow's lemma

Updated on
Edit
Like
Comment
Share on FacebookTweet on TwitterShare on LinkedInShare on Reddit

Chow's lemma, named after Wei-Liang Chow, is one of the foundational results in algebraic geometry. It roughly says that a proper morphism is fairly close to being a projective morphism. More precisely, a version of it states the following:

Contents

If X is a scheme that is proper over a noetherian base S , then there exists a projective S -scheme X and a surjective S -morphism f : X X that induces an isomorphism f 1 ( U ) U for some dense open U X .

Proof

The proof here is a standard one (cf. EGA II, 5.6.1).

It is easy to reduce to the case when X is irreducible, as follows. X is noetherian since it is of finite type over a noetherian base. Then it's also topologically noetherian, and consists of a finite number of irreducible components X i , which are each proper over S (because they're closed immersions in the scheme X which is proper over S ). If, within each of these irreducible components, there exists a dense open U i X i , then we can take U := ( U i i j X j ) . It is not hard to see that each of the disjoint pieces are dense in their respective X i , so the full set U is dense in X . In addition, it's clear that we can similarly find a morphism g which satisfies the density condition.

Having reduced the problem, we now assume X is irreducible. We recall that it must also be noetherian. Thus, we can find a finite open affine cover X = i = 1 n U i . U i are quasi-projective over S ; there are open immersions over S , ϕ i : U i P i into some projective S -schemes P i . Put U = U i . U is nonempty since X is irreducible. Let

ϕ : U P = P 1 × S × S P n .

be given by ϕ i 's restricted to U over S . Let

ψ : U X × S P .

be given by U X and ϕ over S . ψ is then an immersion; thus, it factors as an open immersion followed by a closed immersion X X × S P . Let f : X X be the immersion followed by the projection. We claim f induces f 1 ( U ) U ; for that, it is enough to show f 1 ( U ) = ψ ( U ) . But this means that ψ ( U ) is closed in U × S P . ψ factorizes as U Γ ϕ U × S P X × S P . P is separated over S and so the graph morphism Γ ϕ is a closed immersion. This proves our contention.

It remains to show X is projective over S . Let g : X P be the closed immersion followed by the projection. Showing that g is a closed immersion shows X is projective over S . This can be checked locally. Identifying U i with its image in P i we suppress ϕ i from our notation.

Let V i = p i 1 ( U i ) where p i : P P i . We claim g 1 ( V i ) are an open cover of X . This would follow from f 1 ( U i ) g 1 ( V i ) as sets. This in turn follows from f = p i g on U i as functions on the underlying topological space. Thus it is enough to show that for each i the map g : g 1 ( V i ) V i , denoted by h , is a closed immersion (since the property of being a closed immersion is local on the base).

Fix i . Let Z be the graph of u : V i p i U i X . It is a closed subscheme of X × S V i since X is separated over S . Let q 1 : X × S P X ,   q 2 : X × S P P be the projections. We claim that h factors through Z , which would imply h is a closed immersion. But for w : U V i we have:

v = Γ u w q 1 v = u q 2 v q 1 ψ = u q 2 ψ q 1 ψ = u ϕ .

The last equality holds and thus there is w that satisfies the first equality. This proves our claim.

Additional statements

In the statement of Chow's lemma, if X is reduced, irreducible, or integral, we can assume that the same holds for X . If both X and X are irreducible, then f : X X is a birational morphism. (cf. EGA II, 5.6).

References

Chow's lemma Wikipedia