Nisha Rathode (Editor)

Astrid Suurbeek

Updated on
Edit
Like
Comment
Share on FacebookTweet on TwitterShare on LinkedInShare on Reddit
Country (sports)
  
Netherlands

Wimbledon
  
3R (1968 )

Height
  
1.58 m

Australian Open
  
QF (1968)

Role
  
Tennis Player

Wimbledon
  
2R (1967, 1968, 1969)

Name
  
Astrid Suurbeek

Australian Open
  
QF (1968)

Australian Open
  
2R (1968)


Astrid Suurbeek

Born
  
15 February 1947 (age 77) (
1947-02-15
)

Astrid Suurbeek (born 15 February 1947) is a former Dutch tennis player who was mainly active in the late sixties.

Astrid Suurbeek Astrid Suurbeek Wikipedia

Career

Suurbeek won the singles Dutch championship at Scheveningen in 1967 and 1982 as well as the doubles and mixed doubles in 1968.

She competed in the 1967 Summer Universiade in Tokyo and won the women's doubles Gold medal with Ada Bakker.

Suurbeek played for the Dutch Federation Cup team that reached the 1968 final against Australia, which was played at the Stade Roland Garros in Paris. In the final, she played Australian multiple Grand Slam winner Margaret Court and lost in straight sets, 1–6, 3–6. Australia won the final 3–0. In the same year, she reached the women's singles quarterfinals of the Australian Open which she lost to eventual champion Billie Jean King.

Suurbeek played in the ladies' singles competition at Wimbledon in 1967, 1968 and 1969 but did not make it past the second round.

In 1980, she was voted Female Player of the Year by the USA Tennis Florida Adult Competitive Tennis Council. In 1983 she won the USTA National Indoor Women`s 35 Championships in St. Louis and was ranked first in the USTA women`s 35s.

She is currently head Tennis professional Gleneagles Country Club, Delray, Florida.

References

Astrid Suurbeek Wikipedia


Similar Topics