Dates 19–27 November 2006 | ||
 | ||
Teams 34 (from 1 confederation) Champions United States (6th title) | ||
The 2006 CONCACAF Women's Gold Cup was the third edition of the CONCACAF Women's Gold Cup, and also acted as a qualifier tournament for the 2007 FIFA Women's World Cup. The tournament finals took place in the United States of America between 19 November and 27 November 2006. The USA and Canada received byes into the tournament after contesting the final of the 2002 Gold Cup, while four other spots were determined through regional qualification.
Contents
The United States won the competition with Canada the runner-up. Both squads automatically qualified for the 2007 Women's World Cup, while third place Mexico lost to AFC fourth-place finisher Japan in a playoff for a spot.
UNCAF/NAFU Qualifying
The group winners qualified for the Gold Cup finals.
Group A
Group B
CFU Qualifying
Also known as the Women's Caribbean Cup, there were two spots available for the 22 teams taking part.
Preliminary round
Antigua and Barbuda won 1–0 on aggregate.
Netherlands Antilles won 3–1 on aggregate.
US Virgin Islands won 8–1 on aggregate.
First round
The group winners, in bold, qualified for the final round. Haiti were unable to participate in group B, as they were denied entry to the hosting country Aruba, and thus a play-off between the winners of group B, Suriname, and Haiti was arranged. Haiti won the play-off, but Suriname qualified as best runners-up owing to goal difference, along with Bermuda.
Group A
Group B
Playoff
Group C
Group D
Final round
Trinidad & Tobago hosted the final round, consisting of two groups of three teams, between 6 September and 10 September. The winner of each group, in bold, have qualified for the Gold Cup finals.