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1969 CONCACAF Champions' Cup

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Runners-up
  
Comunicaciones

Dates
  
25 Apr 1969 – 30 Sep 1969

Third place
  
Deportivo Saprissa

Matches played
  
18

Champion
  
Cruz Azul

Teams
  
10

Goals scored
  
53

1969 CONCACAF Champions' Cup

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1970 CONCACAF Champions' Cup

The 1969 CONCACAF Champions' Cup was the 5th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region.

Contents

The tournament was played by 10 teams of 9 nations: Netherlands Antilles, Bermuda, El Salvador, Haiti, Guatemala, Honduras, Mexico, Nicaragua, Costa Rica.

It was played from 25 April till 30 September 1969 under the home/away match system and for the first time, the teams were not split into zones, playing in a straight round system.

Club Deportivo Cruz Azul from Mexico won the final, and became for the first time in its history CONCACAF champion.

First round

  • Saprissa won 5–1 on aggregate score.
  • Comunicaciones won 4–1 on aggregate score.
  • Águila won 5–3 on aggregate score.
  • Somerset Cricket won 6–1 on aggregate score.

    • Second round

  • Toluca won 1–0 on aggregate score. Toluca were disqualified for the undue alignment of three players; Cruz Azul advanced.
  • Comunicaciones won 7–4 on aggregate score.
  • Saprissa won 7–0 on aggregate score.

    • Semifinal

  • Cruz Azul won 4–3 on aggregate score.

    • Final

  • Cruz Azul won 1–0 on aggregate score.

    • References

    1969 CONCACAF Champions' Cup Wikipedia
    (Text) CC BY-SA